Skip to content

平成24年度 春期 ITパスポート試験 問88

This question's explanation and your answers so far.

問88
頻出度★★☆

F さんは,次の選定要件に従って,部内で使用する事務機の機種を選定するための検討資料を作成するよう上司から指示された。 〔選定要件〕 (1) 類似する4機種(機種 A~D)の中からいずれか1機種を選定する。 (2) 評価項目は,価格,性能,サービスの三つとする。評価項目には,いずれを重視するかによって1~5の重みを付ける。 (3) 機種ごとに評価項目の評価値を決める。評価値は1~9のいずれかである。 (4) 評価項目の重みと評価値から総合評価値を計算し,総合評価値の最も大きい機種を選定する。 F さんは,表1の評価表を作って検討することにした。このとき,機種 A の総合評価値は次式で計算する。機種 B~D についても同様である。 機種 A の総合評価値 = w1×a1+w2×a2+w3×a3 なお,記号の意味は次のとおりである。 w1~w3:価格,性能,サービスのそれぞれの評価項目の重み a1~a3:機種 A の価格,性能,サービスのそれぞれの評価値 表1 評価表

評価項目重み機種 A機種 B機種 C機種 D
価格w1a1b1c1d1
性能w2a2b2c2d2
サービスw3a3b3c3d3

Fさんは,作成した評価表案の評価値を上司に見直してもらい,最終的に次の表6の評価表を使って検討資料を作成した。このとき,選定要件に従って選定される機種はどれか。 表6 評価表

評価項目重み機種A機種B機種C機種D
価格27755
性能26337
サービス15784
出典 平成24年度 春期 ITパスポート試験 問88
解説

問 88

  • ア

    正解 The correct answer is ア (Model A). The selection requirements of this question set state that an overall evaluation score is calculated from the weights and the evaluation values of the evaluation items, and that the model with the largest overall evaluation score is selected. The formula is: overall evaluation score = (weight of price × evaluation value of price) + (weight of performance × evaluation value of performance) + (weight of service × evaluation value of service). In Table 6 the weights are 2 for price, 2 for performance, and 1 for service, so calculating each model in turn gives the following. Model A = 2×7 + 2×6 + 1×5 = 14 + 12 + 5 = 31. Model B = 2×7 + 2×3 + 1×7 = 14 + 6 + 7 = 27. Model C = 2×5 + 2×3 + 1×8 = 10 + 6 + 8 = 24. Model D = 2×5 + 2×7 + 1×4 = 10 + 14 + 4 = 28. The overall evaluation scores line up as Model A (31) > Model D (28) > Model B (27) > Model C (24), so the largest is Model A. What works in Model A's favor is that it earns high evaluation values on both items that carry the larger weight of 2: price 7 and performance 6. Therefore the model selected according to the selection requirements is Model A, and the answer is ア.

  • Incorrectイ

    Model B's overall evaluation score is 2×7 + 2×3 + 1×7 = 27, which does not reach Model A's 31 and leaves it in third place. Its price of 7 and service of 7 are high, but its evaluation value for performance, an item with the larger weight of 2, is only 3, so it falls behind Model A by (6−3)×2 = 6 points on performance. Even though it beats Model A by 2 points on service, the weight of service is only 1, so the gap it can recover is just 2 points, and it cannot overtake Model A.

  • Incorrectウ

    Model C's overall evaluation score is 2×5 + 2×3 + 1×8 = 24, the lowest of the four models. Its evaluation value of 8 for service is the highest among the four models, but the weight of service is 1, the smallest, so its contribution to the overall evaluation score is only 8 points. Meanwhile the items with a weight of 2 are low: price is 5 and performance is 3. This makes it a typical example of a model that is not selected because the heavily weighted items score low, even though it is the best on one single item.

  • Incorrectエ

    Model D's overall evaluation score is 2×5 + 2×7 + 1×4 = 28, second only to Model A's 31. Its performance of 7 is the highest among the four models, and on performance alone it does beat Model A (6), but its price of 5 is 2 lower than Model A's 7, and since price carries a weight of 2 that is a disadvantage of 4 points; its service of 4 is also 1 lower than Model A's 5. On balance it ends up 3 points short of Model A, so it is not the one selected by the overall evaluation.

ここがポイント
  • Weighted overall evaluation (weighted scoring) — when comparing several options, give each evaluation item a weight that expresses its importance, compute overall evaluation score = Σ (weight × evaluation value), and choose the option with the largest total. It is a basic technique used when selecting equipment models, suppliers, or proposals, and the calculation is simply a column-wise sum of weight × evaluation value for each model.
  • Judge by the overall evaluation score, not by the highest value on a single item — as with Model C's service of 8 or Model D's performance of 7, being the best on one item does not decide the result when that item's weight is small. The option that scores high on the heavily weighted items (price and performance, each weighted 2, in this question) is the one that gains the advantage, and what the question tests is whether you understand how the weights work.
用語

Your answers